What are the solutions to the equation 2x(x+9)(x^2-2)=0 ?

The solutions to the equation 2x(x+9)(x^2-2)=0 are x=0,x=-9,x=-sqrt(2),x=sqrt(2)

Find the zeros of 2x(x+9)(x^2-2)=0

The zeros of 2x(x+9)(x^2-2)=0 are x=0,x=-9,x=-sqrt(2),x=sqrt(2)

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2 x (x + 9) (x^{2} - 2) = 0

x = 0, x = - 9, x = - 2, x = 2

Decimal Notation

x = 0, x = - 9, x = - 1.41421 \dots, x = 1.41421 \dots

Solution steps

2 x (x + 9) (x^{2} - 2) = 0

Factor

2 x (x + 9) (x^{2} - 2) : 2 x (x + 9) (x + 2) (x - 2)

2 x (x + 9) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 9 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 9 = 0 : x = - 9

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - 9, x = - 2, x = 2

2 x^{3} - 4 x + 5 = 0

10 x^{4} - 9 x^{2} + 2 = 0

x^{4} + 6 x^{2} + 25 = 0

x^{5} - 15 x^{3} + 10 x^{2} + 60 x - 72 = 0

x^{3} - 6 x^{2} + 5 x + 12 = 0

What are the solutions to the equation 2x(x+9)(x^2-2)=0 ?
The solutions to the equation 2x(x+9)(x^2-2)=0 are x=0,x=-9,x=-sqrt(2),x=sqrt(2)
Find the zeros of 2x(x+9)(x^2-2)=0
The zeros of 2x(x+9)(x^2-2)=0 are x=0,x=-9,x=-sqrt(2),x=sqrt(2)