What are the solutions to the equation x^3-6x^2+5x+12=0 ?

The solutions to the equation x^3-6x^2+5x+12=0 are x=-1,x=3,x=4

Find the zeros of x^3-6x^2+5x+12=0

The zeros of x^3-6x^2+5x+12=0 are x=-1,x=3,x=4

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x^{3} - 6 x^{2} + 5 x + 12 = 0

x = - 1, x = 3, x = 4

Solution steps

x^{3} - 6 x^{2} + 5 x + 12 = 0

Factor

x^{3} - 6 x^{2} + 5 x + 12 : (x + 1) (x - 3) (x - 4)

(x + 1) (x - 3) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 3 = 0 or x - 4 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 3 = 0 : x = 3

Solve

x - 4 = 0 : x = 4

The solutions are

x = - 1, x = 3, x = 4

3 x^{4} - 4 x^{3} + 4 x^{2} - 4 x + 1 = 0

x^{3} - 12 x - 11 = 0

2 (x^{2} - 36) (x^{2} + 49) = 0

x^{3} - 5 x^{2} - x - 1 = 0

x^{3} - 4 x^{2} + 7 x - 1 = 0

What are the solutions to the equation x^3-6x^2+5x+12=0 ?
The solutions to the equation x^3-6x^2+5x+12=0 are x=-1,x=3,x=4
Find the zeros of x^3-6x^2+5x+12=0
The zeros of x^3-6x^2+5x+12=0 are x=-1,x=3,x=4