What are the solutions to the equation 2(x^2-36)(x^2+49)=0 ?

The solutions to the equation 2(x^2-36)(x^2+49)=0 are x=-6,x=6,x=7i,x=-7i

Find the zeros of 2(x^2-36)(x^2+49)=0

The zeros of 2(x^2-36)(x^2+49)=0 are x=-6,x=6,x=7i,x=-7i

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2 (x^{2} - 36) (x^{2} + 49) = 0

x = - 6, x = 6, x = 7 i, x = - 7 i

Solution steps

2 (x^{2} - 36) (x^{2} + 49) = 0

Factor

2 (x^{2} - 36) (x^{2} + 49) : 2 (x + 6) (x - 6) (x^{2} + 49)

2 (x + 6) (x - 6) (x^{2} + 49) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 6 = 0 or x - 6 = 0 or x^{2} + 49 = 0

Solve

x + 6 = 0 : x = - 6

Solve

x - 6 = 0 : x = 6

Solve

x^{2} + 49 = 0 : x = 7 i, x = - 7 i

The solutions are

x = - 6, x = 6, x = 7 i, x = - 7 i

x^{3} - 5 x^{2} - x - 1 = 0

x^{3} - 4 x^{2} + 7 x - 1 = 0

4 x = x^{3} + 3 x^{2}

x (x + 3) (x - 1) = 0

x^{3} + x^{2} = 25 x + 25

What are the solutions to the equation 2(x^2-36)(x^2+49)=0 ?
The solutions to the equation 2(x^2-36)(x^2+49)=0 are x=-6,x=6,x=7i,x=-7i
Find the zeros of 2(x^2-36)(x^2+49)=0
The zeros of 2(x^2-36)(x^2+49)=0 are x=-6,x=6,x=7i,x=-7i