What are the solutions to the equation x(x+3)(x-1)=0 ?

The solutions to the equation x(x+3)(x-1)=0 are x=0,x=-3,x=1

Find the zeros of x(x+3)(x-1)=0

The zeros of x(x+3)(x-1)=0 are x=0,x=-3,x=1

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x (x + 3) (x - 1) = 0

x = 0, x = - 3, x = 1

Solution steps

x (x + 3) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 3 = 0 or x - 1 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 1 = 0 : x = 1

The solutions are

x = 0, x = - 3, x = 1

x^{3} + x^{2} = 25 x + 25

x^{3} + 2 x^{2} - 5 x + 1 = 0

x^{3} - 5 x^{2} + 8 x - 6 = 0

6 = \frac{8 x ^{5}}{5} + b

c^{3} - c^{2} + c - 6 = 0

What are the solutions to the equation x(x+3)(x-1)=0 ?
The solutions to the equation x(x+3)(x-1)=0 are x=0,x=-3,x=1
Find the zeros of x(x+3)(x-1)=0
The zeros of x(x+3)(x-1)=0 are x=0,x=-3,x=1