What are the solutions to the equation x^3-5x^2+8x-6=0 ?

The solutions to the equation x^3-5x^2+8x-6=0 are x=3,x=1+i,x=1-i

Find the zeros of x^3-5x^2+8x-6=0

The zeros of x^3-5x^2+8x-6=0 are x=3,x=1+i,x=1-i

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x^{3} - 5 x^{2} + 8 x - 6 = 0

x = 3, x = 1 + i, x = 1 - i

Solution steps

x^{3} - 5 x^{2} + 8 x - 6 = 0

Factor

x^{3} - 5 x^{2} + 8 x - 6 : (x - 3) (x^{2} - 2 x + 2)

(x - 3) (x^{2} - 2 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x^{2} - 2 x + 2 = 0

Solve

x - 3 = 0 : x = 3

Solve

x^{2} - 2 x + 2 = 0 : x = 1 + i, x = 1 - i

The solutions are

x = 3, x = 1 + i, x = 1 - i

6 = \frac{8 x ^{5}}{5} + b

c^{3} - c^{2} + c - 6 = 0

x, 25 x^{4} - 625 y - 500 = 0

2 x^{3} + 10 x^{2} + 12 x = 0

0 = 2 x^{3} + 3

What are the solutions to the equation x^3-5x^2+8x-6=0 ?
The solutions to the equation x^3-5x^2+8x-6=0 are x=3,x=1+i,x=1-i
Find the zeros of x^3-5x^2+8x-6=0
The zeros of x^3-5x^2+8x-6=0 are x=3,x=1+i,x=1-i