What are the solutions to the equation x^2-10x+19=0 ?

The solutions to the equation x^2-10x+19=0 are x=5+sqrt(6),x=5-sqrt(6)

Find the zeros of x^2-10x+19=0

The zeros of x^2-10x+19=0 are x=5+sqrt(6),x=5-sqrt(6)

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x^{2} - 10 x + 19 = 0

x = 5 + 6, x = 5 - 6

Decimal Notation

x = 7.44948 \dots, x = 2.55051 \dots

Solution steps

x^{2} - 10 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 19 = 26

x_{1, 2} = \frac{- ( - 10 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 6}{2 \cdot 1} : 5 + 6

x = \frac{- ( - 10 ) - 2 6}{2 \cdot 1} : 5 - 6

The solutions to the quadratic equation are:

x = 5 + 6, x = 5 - 6

x^{2} - 18 x y + 80 y^{2}

(- \frac{4}{5})^{2}

3 x^{2} + 240 = 0

\frac{- 4}{3 ^{2}}

3 e^{- 1}

What are the solutions to the equation x^2-10x+19=0 ?
The solutions to the equation x^2-10x+19=0 are x=5+sqrt(6),x=5-sqrt(6)
Find the zeros of x^2-10x+19=0
The zeros of x^2-10x+19=0 are x=5+sqrt(6),x=5-sqrt(6)