What are the solutions to the equation 3x^2-5x=5x-7 ?

The solutions to the equation 3x^2-5x=5x-7 are x= 7/3 ,x=1

Find the zeros of 3x^2-5x=5x-7

The zeros of 3x^2-5x=5x-7 are x= 7/3 ,x=1

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3 x^{2} - 5 x = 5 x - 7

x = \frac{7}{3}, x = 1

Decimal Notation

x = 2.33333 \dots, x = 1

Solution steps

3 x^{2} - 5 x = 5 x - 7

Move

7

to the left side

3 x^{2} - 5 x + 7 = 5 x

Move

5 x

to the left side

3 x^{2} - 10 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

(- 10)^{2} - 4 \cdot 3 \cdot 7 = 4

x_{1, 2} = \frac{- ( - 10 ) \pm 4}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4}{2 \cdot 3}, x_{2} = \frac{- ( - 10 ) - 4}{2 \cdot 3}

x = \frac{- ( - 10 ) + 4}{2 \cdot 3} : \frac{7}{3}

x = \frac{- ( - 10 ) - 4}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = 1

- 7 \leq 0

- 3 < x < 0

3 x^{2} + 15 x - 24 = 0

p^{2} + 18 p - 3 = 0

0 = (x + 3)^{2} - 4

What are the solutions to the equation 3x^2-5x=5x-7 ?
The solutions to the equation 3x^2-5x=5x-7 are x= 7/3 ,x=1
Find the zeros of 3x^2-5x=5x-7
The zeros of 3x^2-5x=5x-7 are x= 7/3 ,x=1