What are the solutions to the equation p^2+18p-3=0 ?

The solutions to the equation p^2+18p-3=0 are p=-9+2sqrt(21),p=-9-2sqrt(21)

Find the zeros of p^2+18p-3=0

The zeros of p^2+18p-3=0 are p=-9+2sqrt(21),p=-9-2sqrt(21)

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p^{2} + 18 p - 3 = 0

p = - 9 + 221, p = - 9 - 221

Decimal Notation

p = 0.16515 \dots, p = - 18.16515 \dots

Solution steps

p^{2} + 18 p - 3 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot (- 3) = 421

p_{1, 2} = \frac{- 18 \pm 4 21}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 18 + 4 21}{2 \cdot 1}, p_{2} = \frac{- 18 - 4 21}{2 \cdot 1}

p = \frac{- 18 + 4 21}{2 \cdot 1} : - 9 + 221

p = \frac{- 18 - 4 21}{2 \cdot 1} : - 9 - 221

The solutions to the quadratic equation are:

p = - 9 + 221, p = - 9 - 221

0 = (x + 3)^{2} - 4

2 x^{2} + 7 x - 4 \leq 0

d^{2} - 12 d + 36

x^{2} + 16 x - 2 = 0

\frac{2 x ^{2} + 2 x}{3 x ^{2} + 3 x}

What are the solutions to the equation p^2+18p-3=0 ?
The solutions to the equation p^2+18p-3=0 are p=-9+2sqrt(21),p=-9-2sqrt(21)
Find the zeros of p^2+18p-3=0
The zeros of p^2+18p-3=0 are p=-9+2sqrt(21),p=-9-2sqrt(21)