What are the solutions to the equation (4x+8)^2(2x-6)^3=0 ?

The solutions to the equation (4x+8)^2(2x-6)^3=0 are x=-2,x=3

Find the zeros of (4x+8)^2(2x-6)^3=0

The zeros of (4x+8)^2(2x-6)^3=0 are x=-2,x=3

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(4 x + 8)^{2} (2 x - 6)^{3} = 0

x = - 2, x = 3

Solution steps

(4 x + 8)^{2} (2 x - 6)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 8 = 0 or 2 x - 6 = 0

Solve

4 x + 8 = 0 : x = - 2

Solve

2 x - 6 = 0 : x = 3

The solutions are

x = - 2, x = 3

x^{3} - 3 x^{2} - 3 x + 9 = 0

x, 7 x^{6} = y^{2} x

x, x^{4} - 4 x^{2} - y = 0

- 5 s s^{2} - 16 + 8 s + 4 = 1 s - 4

x^{3} - 6 x^{2} + 3 x + 3 = 0

What are the solutions to the equation (4x+8)^2(2x-6)^3=0 ?
The solutions to the equation (4x+8)^2(2x-6)^3=0 are x=-2,x=3
Find the zeros of (4x+8)^2(2x-6)^3=0
The zeros of (4x+8)^2(2x-6)^3=0 are x=-2,x=3