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Popular >

2x^2+7x-4<= 0

Solution

2 x^{2} + 7 x - 4 \leq 0

Solution

- 4 \leq x \leq \frac{1}{2}

+2

Interval Notation

[- 4, \frac{1}{2}]

Decimal Notation

- 4 \leq x \leq 0.5

Solution steps

2 x^{2} + 7 x - 4 \leq 0

Factor

2 x^{2} + 7 x - 4 : (2 x - 1) (x + 4)

(2 x - 1) (x + 4) \leq 0

Identify the intervals

- 4 \leq x \leq \frac{1}{2}

Popular Examples

factor d^2-12d+36 factor

d^{2} - 12 d + 36

x^{2} + 16 x - 2 = 0

factor (2x^2+2x)/(3x^2+3x)factor

\frac{2 x ^{2} + 2 x}{3 x ^{2} + 3 x}

factor 2x^2+6x-36 factor

2 x^{2} + 6 x - 36

1/5 x^5-x^4-5/3 x^3>= 0

\frac{1}{5} x^{5} - x^{4} - \frac{5}{3} x^{3} \geq 0

Frequently Asked Questions (FAQ)

What is 2x^2+7x-4<= 0 ?
The solution to 2x^2+7x-4<= 0 is -4<= x<= 1/2