What are the solutions to the equation x^2+16x-2=0 ?

The solutions to the equation x^2+16x-2=0 are x=-8+sqrt(66),x=-8-sqrt(66)

Find the zeros of x^2+16x-2=0

The zeros of x^2+16x-2=0 are x=-8+sqrt(66),x=-8-sqrt(66)

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x^{2} + 16 x - 2 = 0

x = - 8 + 66, x = - 8 - 66

Decimal Notation

x = 0.12403 \dots, x = - 16.12403 \dots

Solution steps

x^{2} + 16 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 2) = 266

x_{1, 2} = \frac{- 16 \pm 2 66}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 66}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 66}{2 \cdot 1}

x = \frac{- 16 + 2 66}{2 \cdot 1} : - 8 + 66

x = \frac{- 16 - 2 66}{2 \cdot 1} : - 8 - 66

The solutions to the quadratic equation are:

x = - 8 + 66, x = - 8 - 66

\frac{2 x ^{2} + 2 x}{3 x ^{2} + 3 x}

2 x^{2} + 6 x - 36

\frac{1}{5} x^{5} - x^{4} - \frac{5}{3} x^{3} \geq 0

(5 x + 3) \cdot (x - \frac{1}{5}) + 2 = 3

1.2 x = 6

What are the solutions to the equation x^2+16x-2=0 ?
The solutions to the equation x^2+16x-2=0 are x=-8+sqrt(66),x=-8-sqrt(66)
Find the zeros of x^2+16x-2=0
The zeros of x^2+16x-2=0 are x=-8+sqrt(66),x=-8-sqrt(66)