What are the solutions to the equation (5x+3)*(x-1/5)+2=3 ?

The solutions to the equation (5x+3)*(x-1/5)+2=3 are x= 2/5 ,x=-4/5

Find the zeros of (5x+3)*(x-1/5)+2=3

The zeros of (5x+3)*(x-1/5)+2=3 are x= 2/5 ,x=-4/5

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(5 x + 3) \cdot (x - \frac{1}{5}) + 2 = 3

x = \frac{2}{5}, x = - \frac{4}{5}

Decimal Notation

x = 0.4, x = - 0.8

Solution steps

(5 x + 3) (x - \frac{1}{5}) + 2 = 3

Expand

(5 x + 3) (x - \frac{1}{5}) + 2 : 5 x^{2} + 2 x + \frac{7}{5}

5 x^{2} + 2 x + \frac{7}{5} = 3

Move

3

to the left side

5 x^{2} + 2 x - \frac{8}{5} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 5 ( - \frac{8}{5} )}{2 \cdot 5}

2^{2} - 4 \cdot 5 (- \frac{8}{5}) = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 \cdot 5}, x_{2} = \frac{- 2 - 6}{2 \cdot 5}

x = \frac{- 2 + 6}{2 \cdot 5} : \frac{2}{5}

x = \frac{- 2 - 6}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - \frac{4}{5}

1.2 x = 6

\frac{x - 6}{x - 9} > 0

2 x^{2} - 5 x - 52 = 0

2 (4 x - 5) = 7 x

w^{3} - 64

What are the solutions to the equation (5x+3)*(x-1/5)+2=3 ?
The solutions to the equation (5x+3)*(x-1/5)+2=3 are x= 2/5 ,x=-4/5
Find the zeros of (5x+3)*(x-1/5)+2=3
The zeros of (5x+3)*(x-1/5)+2=3 are x= 2/5 ,x=-4/5