What are the solutions to the equation 2x^3-12x^2-8x+48=0 ?

The solutions to the equation 2x^3-12x^2-8x+48=0 are x=6,x=-2,x=2

Find the zeros of 2x^3-12x^2-8x+48=0

The zeros of 2x^3-12x^2-8x+48=0 are x=6,x=-2,x=2

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2 x^{3} - 12 x^{2} - 8 x + 48 = 0

x = 6, x = - 2, x = 2

Solution steps

2 x^{3} - 12 x^{2} - 8 x + 48 = 0

Factor

2 x^{3} - 12 x^{2} - 8 x + 48 : 2 (x - 6) (x + 2) (x - 2)

2 (x - 6) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x - 6 = 0 : x = 6

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 6, x = - 2, x = 2

x^{3} + 2 x^{2} = 16 x + 32

n^{3} = 256

x^{5} + 32 i = 0

0 = x^{3} + 6 x^{2} - 15 x + 8

x^{4} + 625 = 0

What are the solutions to the equation 2x^3-12x^2-8x+48=0 ?
The solutions to the equation 2x^3-12x^2-8x+48=0 are x=6,x=-2,x=2
Find the zeros of 2x^3-12x^2-8x+48=0
The zeros of 2x^3-12x^2-8x+48=0 are x=6,x=-2,x=2