What are the solutions to the equation x^3=0.125 ?

The solutions to the equation x^3=0.125 are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i

Find the zeros of x^3=0.125

The zeros of x^3=0.125 are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i

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x^{3} = 0.125

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

Solution steps

x^{3} = 0.125

For

x^{3} = f (a)

the solutions are

Simplify

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

x^{3} + 5 x + 6 = 0

4 x^{3} + x - 1 = 0

180 x^{3} + 36 x^{2} - 5 x - 1 = 0

x^{3} + 25.3 x^{2} + 219 x + 660.1 = 0

x^{4} - 6 x^{3} + 13 x^{2} - 12 x + 4 = 0

What are the solutions to the equation x^3=0.125 ?
The solutions to the equation x^3=0.125 are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i
Find the zeros of x^3=0.125
The zeros of x^3=0.125 are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i