What are the solutions to the equation 12x^3+18x^2-18x-12=0 ?

The solutions to the equation 12x^3+18x^2-18x-12=0 are x=1,x=-1/2 ,x=-2

Find the zeros of 12x^3+18x^2-18x-12=0

The zeros of 12x^3+18x^2-18x-12=0 are x=1,x=-1/2 ,x=-2

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12 x^{3} + 18 x^{2} - 18 x - 12 = 0

x = 1, x = - \frac{1}{2}, x = - 2

Decimal Notation

x = 1, x = - 0.5, x = - 2

Solution steps

12 x^{3} + 18 x^{2} - 18 x - 12 = 0

Factor

12 x^{3} + 18 x^{2} - 18 x - 12 : 6 (x - 1) (2 x + 1) (x + 2)

6 (x - 1) (2 x + 1) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x + 1 = 0 or x + 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x + 2 = 0 : x = - 2

The solutions are

x = 1, x = - \frac{1}{2}, x = - 2

(5 y^{4})^{3} = 125 y^{24}

z^{8} + 1 = 3 i

2 x^{3} - 6 x^{2} + 2 x + 8 = 0

5 x^{3} + 2 x^{3} + 3 x^{6} = 39

5 p (2 p - 3) (p + 7) = 0

What are the solutions to the equation 12x^3+18x^2-18x-12=0 ?
The solutions to the equation 12x^3+18x^2-18x-12=0 are x=1,x=-1/2 ,x=-2
Find the zeros of 12x^3+18x^2-18x-12=0
The zeros of 12x^3+18x^2-18x-12=0 are x=1,x=-1/2 ,x=-2