What are the solutions to the equation 5p(2p-3)(p+7)=0 ?

The solutions to the equation 5p(2p-3)(p+7)=0 are p=0,p= 3/2 ,p=-7

Find the zeros of 5p(2p-3)(p+7)=0

The zeros of 5p(2p-3)(p+7)=0 are p=0,p= 3/2 ,p=-7

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5 p (2 p - 3) (p + 7) = 0

p = 0, p = \frac{3}{2}, p = - 7

Decimal Notation

p = 0, p = 1.5, p = - 7

Solution steps

5 p (2 p - 3) (p + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

p = 0 or 2 p - 3 = 0 or p + 7 = 0

Solve

2 p - 3 = 0 : p = \frac{3}{2}

Solve

p + 7 = 0 : p = - 7

The solutions are

p = 0, p = \frac{3}{2}, p = - 7

2 x^{3} - 14 x^{2} + 24 x = 0

3 x^{3} - 27 x^{2} + 54 x = 0

x^{3} - 88 x + 96 = 0

- λ^{3} + 2 λ^{2} + 9 λ - 18 = 0

x^{3} - 3 x - 6 = 0

What are the solutions to the equation 5p(2p-3)(p+7)=0 ?
The solutions to the equation 5p(2p-3)(p+7)=0 are p=0,p= 3/2 ,p=-7
Find the zeros of 5p(2p-3)(p+7)=0
The zeros of 5p(2p-3)(p+7)=0 are p=0,p= 3/2 ,p=-7