What are the solutions to the equation -λ^3+2λ^2+9λ-18=0 ?

The solutions to the equation -λ^3+2λ^2+9λ-18=0 are λ=2,λ=-3,λ=3

Find the zeros of -λ^3+2λ^2+9λ-18=0

The zeros of -λ^3+2λ^2+9λ-18=0 are λ=2,λ=-3,λ=3

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- λ^{3} + 2 λ^{2} + 9 λ - 18 = 0

λ = 2, λ = - 3, λ = 3

Solution steps

- λ^{3} + 2 λ^{2} + 9 λ - 18 = 0

Factor

- λ^{3} + 2 λ^{2} + 9 λ - 18 : - (λ - 2) (λ + 3) (λ - 3)

- (λ - 2) (λ + 3) (λ - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

λ - 2 = 0 or λ + 3 = 0 or λ - 3 = 0

Solve

λ - 2 = 0 : λ = 2

Solve

λ + 3 = 0 : λ = - 3

Solve

λ - 3 = 0 : λ = 3

The solutions are

λ = 2, λ = - 3, λ = 3

x^{3} - 3 x - 6 = 0

s^{4} - 1 = 0

z (z + 9) (4 z + 2) = 0

2 x^{3} + 7 x^{2} - 21 x - 54 = 0

30 x^{4} - 60 x^{2} = 0

What are the solutions to the equation -λ^3+2λ^2+9λ-18=0 ?
The solutions to the equation -λ^3+2λ^2+9λ-18=0 are λ=2,λ=-3,λ=3
Find the zeros of -λ^3+2λ^2+9λ-18=0
The zeros of -λ^3+2λ^2+9λ-18=0 are λ=2,λ=-3,λ=3