What are the solutions to the equation -2(6x+7)(x^2-2)=0 ?

The solutions to the equation -2(6x+7)(x^2-2)=0 are x=-7/6 ,x=-sqrt(2),x=sqrt(2)

Find the zeros of -2(6x+7)(x^2-2)=0

The zeros of -2(6x+7)(x^2-2)=0 are x=-7/6 ,x=-sqrt(2),x=sqrt(2)

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- 2 (6 x + 7) (x^{2} - 2) = 0

x = - \frac{7}{6}, x = - 2, x = 2

Decimal Notation

x = - 1.16666 \dots, x = - 1.41421 \dots, x = 1.41421 \dots

Solution steps

- 2 (6 x + 7) (x^{2} - 2) = 0

Factor

- 2 (6 x + 7) (x^{2} - 2) : - 2 (6 x + 7) (x + 2) (x - 2)

- 2 (6 x + 7) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

6 x + 7 = 0 or x + 2 = 0 or x - 2 = 0

Solve

6 x + 7 = 0 : x = - \frac{7}{6}

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - \frac{7}{6}, x = - 2, x = 2

- x^{3} + 6 x^{2} - 5 x - 12 = 0

x^{6} + 64 x^{4} = 0

x^{3} + 2 x^{2} - 35 x = 0

x^{4} + 38 = 102

x^{6} - 3 x^{4} + 3 x^{2} - 1 = 0

What are the solutions to the equation -2(6x+7)(x^2-2)=0 ?
The solutions to the equation -2(6x+7)(x^2-2)=0 are x=-7/6 ,x=-sqrt(2),x=sqrt(2)
Find the zeros of -2(6x+7)(x^2-2)=0
The zeros of -2(6x+7)(x^2-2)=0 are x=-7/6 ,x=-sqrt(2),x=sqrt(2)