What are the solutions to the equation 27x^2-42x-3x^3=0 ?

The solutions to the equation 27x^2-42x-3x^3=0 are x=0,x=2,x=7

Find the zeros of 27x^2-42x-3x^3=0

The zeros of 27x^2-42x-3x^3=0 are x=0,x=2,x=7

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27 x^{2} - 42 x - 3 x^{3} = 0

x = 0, x = 2, x = 7

Solution steps

27 x^{2} - 42 x - 3 x^{3} = 0

Factor

27 x^{2} - 42 x - 3 x^{3} : - 3 x (x - 2) (x - 7)

- 3 x (x - 2) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0 or x - 7 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 7 = 0 : x = 7

The solutions are

x = 0, x = 2, x = 7

x (x^{2} - 2) = 2

x^{3} + 2 x^{2} - 4 x + 16 = 0

6 \cdot x^{3} = 180

x^{6} + x^{4} + x - 2 = 0

- x^{3} + 3 x^{2} - 2 = 0

What are the solutions to the equation 27x^2-42x-3x^3=0 ?
The solutions to the equation 27x^2-42x-3x^3=0 are x=0,x=2,x=7
Find the zeros of 27x^2-42x-3x^3=0
The zeros of 27x^2-42x-3x^3=0 are x=0,x=2,x=7