What are the solutions to the equation x(x-3)(3-x)-2(3-x)=(x-1)(x-3) ?

The solutions to the equation x(x-3)(3-x)-2(3-x)=(x-1)(x-3) are x=-1,x=3

Find the zeros of x(x-3)(3-x)-2(3-x)=(x-1)(x-3)

The zeros of x(x-3)(3-x)-2(3-x)=(x-1)(x-3) are x=-1,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x (x - 3) (3 - x) - 2 (3 - x) = (x - 1) (x - 3)

x = - 1, x = 3

Solution steps

x (x - 3) (3 - x) - 2 (3 - x) = (x - 1) (x - 3)

Expand

x (x - 3) (3 - x) - 2 (3 - x) : - x^{3} + 6 x^{2} - 7 x - 6

Expand

(x - 1) (x - 3) : x^{2} - 4 x + 3

- x^{3} + 6 x^{2} - 7 x - 6 = x^{2} - 4 x + 3

Move

3

to the left side

- x^{3} + 6 x^{2} - 7 x - 9 = x^{2} - 4 x

Move

4 x

to the left side

- x^{3} + 6 x^{2} - 3 x - 9 = x^{2}

Move

x^{2}

to the left side

- x^{3} + 5 x^{2} - 3 x - 9 = 0

Factor

- x^{3} + 5 x^{2} - 3 x - 9 : - (x + 1) (x - 3)^{2}

- (x + 1) (x - 3)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 1, x = 3

2 x^{10} = 10 x^{2}

1800 - 1505 x^{2} + 118 x^{4} = 0

(x^{2} - 7) (x - 1) = 0

x^{3} - 9 x^{2} - 4 x + 36 = 0

(x - 1)^{5} = - 32

What are the solutions to the equation x(x-3)(3-x)-2(3-x)=(x-1)(x-3) ?
The solutions to the equation x(x-3)(3-x)-2(3-x)=(x-1)(x-3) are x=-1,x=3
Find the zeros of x(x-3)(3-x)-2(3-x)=(x-1)(x-3)
The zeros of x(x-3)(3-x)-2(3-x)=(x-1)(x-3) are x=-1,x=3