What are the solutions to the equation (5-2x)*(x^2-9)=0 ?

The solutions to the equation (5-2x)*(x^2-9)=0 are x=-3,x=3,x= 5/2

Find the zeros of (5-2x)*(x^2-9)=0

The zeros of (5-2x)*(x^2-9)=0 are x=-3,x=3,x= 5/2

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(5 - 2 x) \cdot (x^{2} - 9) = 0

x = - 3, x = 3, x = \frac{5}{2}

Decimal Notation

x = - 3, x = 3, x = 2.5

Solution steps

(5 - 2 x) (x^{2} - 9) = 0

Factor

(5 - 2 x) (x^{2} - 9) : - (x + 3) (x - 3) (2 x - 5)

- (x + 3) (x - 3) (2 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x - 3 = 0 or 2 x - 5 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

Solve

2 x - 5 = 0 : x = \frac{5}{2}

The solutions are

x = - 3, x = 3, x = \frac{5}{2}

x^{3} = 4.2

2 x^{3} + 4 x^{2} - 30 x = 0

x^{3} = 200

2 = x^{5} - x^{3} + 2 x

3 x^{3} + 3 x^{2} + x = 122

What are the solutions to the equation (5-2x)*(x^2-9)=0 ?
The solutions to the equation (5-2x)*(x^2-9)=0 are x=-3,x=3,x= 5/2
Find the zeros of (5-2x)*(x^2-9)=0
The zeros of (5-2x)*(x^2-9)=0 are x=-3,x=3,x= 5/2