What are the solutions to the equation 7x^3+x^2-28x-4=0 ?

The solutions to the equation 7x^3+x^2-28x-4=0 are x=-1/7 ,x=-2,x=2

Find the zeros of 7x^3+x^2-28x-4=0

The zeros of 7x^3+x^2-28x-4=0 are x=-1/7 ,x=-2,x=2

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7 x^{3} + x^{2} - 28 x - 4 = 0

x = - \frac{1}{7}, x = - 2, x = 2

Decimal Notation

x = - 0.14285 \dots, x = - 2, x = 2

Solution steps

7 x^{3} + x^{2} - 28 x - 4 = 0

Factor

7 x^{3} + x^{2} - 28 x - 4 : (7 x + 1) (x + 2) (x - 2)

(7 x + 1) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

7 x + 1 = 0 or x + 2 = 0 or x - 2 = 0

Solve

7 x + 1 = 0 : x = - \frac{1}{7}

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - \frac{1}{7}, x = - 2, x = 2

20 = (5 + (\frac{0.12 x}{10}))^{20}

8 x^{3} - 8 x^{2} + 1 = 0

x^{3} - 7 = 0

\frac{x ^{3}}{2} = 8

- 8 + 3 X^{3} + 2 X = 0

What are the solutions to the equation 7x^3+x^2-28x-4=0 ?
The solutions to the equation 7x^3+x^2-28x-4=0 are x=-1/7 ,x=-2,x=2
Find the zeros of 7x^3+x^2-28x-4=0
The zeros of 7x^3+x^2-28x-4=0 are x=-1/7 ,x=-2,x=2