What are the solutions to the equation 2x^3+x^2-8x+3=0 ?

The solutions to the equation 2x^3+x^2-8x+3=0 are x= 3/2 ,x=-1+sqrt(2),x=-1-sqrt(2)

Find the zeros of 2x^3+x^2-8x+3=0

The zeros of 2x^3+x^2-8x+3=0 are x= 3/2 ,x=-1+sqrt(2),x=-1-sqrt(2)

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2 x^{3} + x^{2} - 8 x + 3 = 0

x = \frac{3}{2}, x = - 1 + 2, x = - 1 - 2

Solution steps

2 x^{3} + x^{2} - 8 x + 3 = 0

Factor

2 x^{3} + x^{2} - 8 x + 3 : (2 x - 3) (x^{2} + 2 x - 1)

(2 x - 3) (x^{2} + 2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 3 = 0 or x^{2} + 2 x - 1 = 0

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

x^{2} + 2 x - 1 = 0 : x = - 1 + 2, x = - 1 - 2

The solutions are

x = \frac{3}{2}, x = - 1 + 2, x = - 1 - 2

4 x^{3} + 23 x^{2} - 2 x = 0

0 = x^{3} - 3 x - 2

4 x^{4} - 33 x^{2} + 50 = 0

a^{4} - a^{2} = 2

2 x^{3} - 31 = 0

What are the solutions to the equation 2x^3+x^2-8x+3=0 ?
The solutions to the equation 2x^3+x^2-8x+3=0 are x= 3/2 ,x=-1+sqrt(2),x=-1-sqrt(2)
Find the zeros of 2x^3+x^2-8x+3=0
The zeros of 2x^3+x^2-8x+3=0 are x= 3/2 ,x=-1+sqrt(2),x=-1-sqrt(2)