What are the solutions to the equation 4x^4-33x^2+50=0 ?

The solutions to the equation 4x^4-33x^2+50=0 are x= 5/2 ,x=-5/2 ,x=sqrt(2),x=-sqrt(2)

Find the zeros of 4x^4-33x^2+50=0

The zeros of 4x^4-33x^2+50=0 are x= 5/2 ,x=-5/2 ,x=sqrt(2),x=-sqrt(2)

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4 x^{4} - 33 x^{2} + 50 = 0

x = \frac{5}{2}, x = - \frac{5}{2}, x = 2, x = - 2

Decimal Notation

x = 2.5, x = - 2.5, x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

4 x^{4} - 33 x^{2} + 50 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

4 u^{2} - 33 u + 50 = 0

Solve

4 u^{2} - 33 u + 50 = 0 : u = \frac{25}{4}, u = 2

u = \frac{25}{4}, u = 2

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = \frac{25}{4} : x = \frac{5}{2}, x = - \frac{5}{2}

Solve

x^{2} = 2 : x = 2, x = - 2

The solutions are

x = \frac{5}{2}, x = - \frac{5}{2}, x = 2, x = - 2

a^{4} - a^{2} = 2

2 x^{3} - 31 = 0

x^{4} - 5 x + 6 = 0

(2 x^{2} - 1)^{2} = 36

(3 y + 18) (y^{2} - 11 y + 30) = 0

What are the solutions to the equation 4x^4-33x^2+50=0 ?
The solutions to the equation 4x^4-33x^2+50=0 are x= 5/2 ,x=-5/2 ,x=sqrt(2),x=-sqrt(2)
Find the zeros of 4x^4-33x^2+50=0
The zeros of 4x^4-33x^2+50=0 are x= 5/2 ,x=-5/2 ,x=sqrt(2),x=-sqrt(2)