What are the solutions to the equation (2x^2-1)^2=36 ?

The solutions to the equation (2x^2-1)^2=36 are x=sqrt(7/2),x=-sqrt(7/2),x=sqrt(5/2)i,x=-sqrt(5/2)i

Find the zeros of (2x^2-1)^2=36

The zeros of (2x^2-1)^2=36 are x=sqrt(7/2),x=-sqrt(7/2),x=sqrt(5/2)i,x=-sqrt(5/2)i

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(2 x^{2} - 1)^{2} = 36

x = \frac{7}{2}, x = - \frac{7}{2}, x = \frac{5}{2} i, x = - \frac{5}{2} i

Solution steps

(2 x^{2} - 1)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x^{2} - 1 = 36 : x = \frac{7}{2}, x = - \frac{7}{2}

Solve

2 x^{2} - 1 = - 36 : x = \frac{5}{2} i, x = - \frac{5}{2} i

The solutions are

x = \frac{7}{2}, x = - \frac{7}{2}, x = \frac{5}{2} i, x = - \frac{5}{2} i

(3 y + 18) (y^{2} - 11 y + 30) = 0

y, x^{2} + y^{3} = c

2 x^{3} + 13 x^{2} + 16 x + 5 = 0

r^{4} - 2 r^{2} + 1 = 0

x^{3} - 4 x - 2 = 1

What are the solutions to the equation (2x^2-1)^2=36 ?
The solutions to the equation (2x^2-1)^2=36 are x=sqrt(7/2),x=-sqrt(7/2),x=sqrt(5/2)i,x=-sqrt(5/2)i
Find the zeros of (2x^2-1)^2=36
The zeros of (2x^2-1)^2=36 are x=sqrt(7/2),x=-sqrt(7/2),x=sqrt(5/2)i,x=-sqrt(5/2)i