What are the solutions to the equation (x^2+8x+15)^5=0 ?

The solutions to the equation (x^2+8x+15)^5=0 are x=-3,x=-5

Find the zeros of (x^2+8x+15)^5=0

The zeros of (x^2+8x+15)^5=0 are x=-3,x=-5

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(x^{2} + 8 x + 15)^{5} = 0

x = - 3, x = - 5

Solution steps

(x^{2} + 8 x + 15)^{5} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x^{2} + 8 x + 15 = 0 : x = - 3, x = - 5

The solutions are

x = - 3, x = - 5

- x^{3} - 6 x^{2} + 124 x + 264 = 0

3 m^{3} + 33 m^{2} + 90 m = 0

- 1 = 7 x^{3} + 1

2 x^{3} - 6 x^{2} + 6 x - 1 = - 5

t^{3} = d (2 + a)

What are the solutions to the equation (x^2+8x+15)^5=0 ?
The solutions to the equation (x^2+8x+15)^5=0 are x=-3,x=-5
Find the zeros of (x^2+8x+15)^5=0
The zeros of (x^2+8x+15)^5=0 are x=-3,x=-5