What are the solutions to the equation x^3-4x^2+4x+16=0 ?

The solutions to the equation x^3-4x^2+4x+16=0 are x\approx-1.39124…

Find the zeros of x^3-4x^2+4x+16=0

The zeros of x^3-4x^2+4x+16=0 are x\approx-1.39124…

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x^{3} - 4 x^{2} + 4 x + 16 = 0

x \approx - 1.39124 \dots

Solution steps

x^{3} - 4 x^{2} + 4 x + 16 = 0

Find one solution for

x^{3} - 4 x^{2} + 4 x + 16 = 0

using Newton-Raphson:

x \approx - 1.39124 \dots

Apply long division:

\frac{x ^{3} - 4 x ^{2} + 4 x + 16}{x + 1.39124 \dots} = x^{2} - 5.39124 \dots x + 11.50051 \dots

x^{2} - 5.39124 \dots x + 11.50051 \dots \approx 0

Find one solution for

x^{2} - 5.39124 \dots x + 11.50051 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx - 1.39124 \dots

12 x^{3} - 48 x^{2} + 48 x = 0

2 x^{3} - x^{2} - 5 x - 2 = 0

2 x^{3} + 2 x + 1 = 0

x^{5} = 5

- 20 x^{3} + 216 x^{2} - 648 x + 432 = 0

What are the solutions to the equation x^3-4x^2+4x+16=0 ?
The solutions to the equation x^3-4x^2+4x+16=0 are x\approx-1.39124…
Find the zeros of x^3-4x^2+4x+16=0
The zeros of x^3-4x^2+4x+16=0 are x\approx-1.39124…