What are the solutions to the equation -x^3+13x^2-40x+36=0 ?

The solutions to the equation -x^3+13x^2-40x+36=0 are x=2,x=9

Find the zeros of -x^3+13x^2-40x+36=0

The zeros of -x^3+13x^2-40x+36=0 are x=2,x=9

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- x^{3} + 13 x^{2} - 40 x + 36 = 0

x = 2, x = 9

Solution steps

- x^{3} + 13 x^{2} - 40 x + 36 = 0

Factor

- x^{3} + 13 x^{2} - 40 x + 36 : - (x - 2)^{2} (x - 9)

- (x - 2)^{2} (x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 9 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 9 = 0 : x = 9

The solutions are

x = 2, x = 9

x^{3} + 3 x^{2} - 2 = 0

16 x^{2} - 30 x - 2 x^{3} = 0

0 = x^{3} + 2 x^{2} - x - 2

x^{3} - x^{2} - 4 x - 4 = 0

X^{3} = 8

What are the solutions to the equation -x^3+13x^2-40x+36=0 ?
The solutions to the equation -x^3+13x^2-40x+36=0 are x=2,x=9
Find the zeros of -x^3+13x^2-40x+36=0
The zeros of -x^3+13x^2-40x+36=0 are x=2,x=9