What are the solutions to the equation 0=x^3+2x^2-x-2 ?

The solutions to the equation 0=x^3+2x^2-x-2 are x=-2,x=-1,x=1

Find the zeros of 0=x^3+2x^2-x-2

The zeros of 0=x^3+2x^2-x-2 are x=-2,x=-1,x=1

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0 = x^{3} + 2 x^{2} - x - 2

x = - 2, x = - 1, x = 1

Solution steps

0 = x^{3} + 2 x^{2} - x - 2

Switch sides

x^{3} + 2 x^{2} - x - 2 = 0

Factor

x^{3} + 2 x^{2} - x - 2 : (x + 2) (x + 1) (x - 1)

(x + 2) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x + 1 = 0 or x - 1 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = - 2, x = - 1, x = 1

x^{3} - x^{2} - 4 x - 4 = 0

X^{3} = 8

x^{3} - 3 x^{2} - 9 x = - 27

t^{4} - 4 t^{2} + 3 = 0

x^{3} - x^{2} - 4 x - 6 = 0

What are the solutions to the equation 0=x^3+2x^2-x-2 ?
The solutions to the equation 0=x^3+2x^2-x-2 are x=-2,x=-1,x=1
Find the zeros of 0=x^3+2x^2-x-2
The zeros of 0=x^3+2x^2-x-2 are x=-2,x=-1,x=1