What are the solutions to the equation -λ^3+3λ^2+9λ+5=0 ?

The solutions to the equation -λ^3+3λ^2+9λ+5=0 are λ=-1,λ=5

Find the zeros of -λ^3+3λ^2+9λ+5=0

The zeros of -λ^3+3λ^2+9λ+5=0 are λ=-1,λ=5

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- λ^{3} + 3 λ^{2} + 9 λ + 5 = 0

λ = - 1, λ = 5

Solution steps

- λ^{3} + 3 λ^{2} + 9 λ + 5 = 0

Factor

- λ^{3} + 3 λ^{2} + 9 λ + 5 : - (λ + 1)^{2} (λ - 5)

- (λ + 1)^{2} (λ - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

λ + 1 = 0 or λ - 5 = 0

Solve

λ + 1 = 0 : λ = - 1

Solve

λ - 5 = 0 : λ = 5

The solutions are

λ = - 1, λ = 5

- x^{3} + 4 x^{2} + 25 x - 100 = 0

9 = x^{5} + x^{3} + x

3 x^{3} - 4 x^{2} - 48 x + 64 = 0

10000 = 1 x^{10}

5 x^{4} - 40 x = 0

What are the solutions to the equation -λ^3+3λ^2+9λ+5=0 ?
The solutions to the equation -λ^3+3λ^2+9λ+5=0 are λ=-1,λ=5
Find the zeros of -λ^3+3λ^2+9λ+5=0
The zeros of -λ^3+3λ^2+9λ+5=0 are λ=-1,λ=5