What are the solutions to the equation 5x^4-40x=0 ?

The solutions to the equation 5x^4-40x=0 are x=0,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

Find the zeros of 5x^4-40x=0

The zeros of 5x^4-40x=0 are x=0,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

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5 x^{4} - 40 x = 0

x = 0, x = 2, x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

5 x^{4} - 40 x = 0

Factor

5 x^{4} - 40 x : 5 x (x^{3} - 8)

5 x (x^{3} - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{3} - 8 = 0

Solve

x^{3} - 8 = 0 : x = 2, x = - 1 + 3 i, x = - 1 - 3 i

The solutions are

x = 0, x = 2, x = - 1 + 3 i, x = - 1 - 3 i

555 = 5 x^{3}

(2 x + 1)^{4} + 4 (2 x + 1)^{2} = 12

x^{4} - 6 x^{2} + 9 = 0

3 x^{3} + 5 x^{2} + 4 x - 1 = 0

2 x^{3} - 3 x^{2} - 8 x - 3 = 0

What are the solutions to the equation 5x^4-40x=0 ?
The solutions to the equation 5x^4-40x=0 are x=0,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i
Find the zeros of 5x^4-40x=0
The zeros of 5x^4-40x=0 are x=0,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i