What are the solutions to the equation 2x^3-3x^2-8x-3=0 ?

The solutions to the equation 2x^3-3x^2-8x-3=0 are x=-1,x=-1/2 ,x=3

Find the zeros of 2x^3-3x^2-8x-3=0

The zeros of 2x^3-3x^2-8x-3=0 are x=-1,x=-1/2 ,x=3

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2 x^{3} - 3 x^{2} - 8 x - 3 = 0

x = - 1, x = - \frac{1}{2}, x = 3

Decimal Notation

x = - 1, x = - 0.5, x = 3

Solution steps

2 x^{3} - 3 x^{2} - 8 x - 3 = 0

Factor

2 x^{3} - 3 x^{2} - 8 x - 3 : (x + 1) (2 x + 1) (x - 3)

(x + 1) (2 x + 1) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 2 x + 1 = 0 or x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 1, x = - \frac{1}{2}, x = 3

v^{3} - 2 v^{2} - 16 v = - 32

r^{4} - 2 r^{3} + 10 r^{2} - 18 r + 9 = 0

0 = x^{3} + 2 x^{2} - 4 x - 8

x, y + 3 = x^{3}

x, y^{4} = - x^{4}

What are the solutions to the equation 2x^3-3x^2-8x-3=0 ?
The solutions to the equation 2x^3-3x^2-8x-3=0 are x=-1,x=-1/2 ,x=3
Find the zeros of 2x^3-3x^2-8x-3=0
The zeros of 2x^3-3x^2-8x-3=0 are x=-1,x=-1/2 ,x=3