What are the solutions to the equation -x^3+7x^2-2x-40=0 ?

The solutions to the equation -x^3+7x^2-2x-40=0 are x=-2,x=4,x=5

Find the zeros of -x^3+7x^2-2x-40=0

The zeros of -x^3+7x^2-2x-40=0 are x=-2,x=4,x=5

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- x^{3} + 7 x^{2} - 2 x - 40 = 0

x = - 2, x = 4, x = 5

Solution steps

- x^{3} + 7 x^{2} - 2 x - 40 = 0

Factor

- x^{3} + 7 x^{2} - 2 x - 40 : - (x + 2) (x - 4) (x - 5)

- (x + 2) (x - 4) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 4 = 0 or x - 5 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 4 = 0 : x = 4

Solve

x - 5 = 0 : x = 5

The solutions are

x = - 2, x = 4, x = 5

x^{4} = 5 x^{2} - 4

4 x^{4} + 4 = 5 x^{2}

(x + 2)^{3} = 27

x^{3} + 2 x^{2} + x + 1 = 0

- 2 x^{3} = 0

What are the solutions to the equation -x^3+7x^2-2x-40=0 ?
The solutions to the equation -x^3+7x^2-2x-40=0 are x=-2,x=4,x=5
Find the zeros of -x^3+7x^2-2x-40=0
The zeros of -x^3+7x^2-2x-40=0 are x=-2,x=4,x=5