What are the solutions to the equation (x+2)^3=27 ?

The solutions to the equation (x+2)^3=27 are x=1,x=-7/2+i(3sqrt(3))/2 ,x=-7/2-i(3sqrt(3))/2

Find the zeros of (x+2)^3=27

The zeros of (x+2)^3=27 are x=1,x=-7/2+i(3sqrt(3))/2 ,x=-7/2-i(3sqrt(3))/2

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(x + 2)^{3} = 27

x = 1, x = - \frac{7}{2} + i \frac{3 3}{2}, x = - \frac{7}{2} - i \frac{3 3}{2}

Solution steps

(x + 2)^{3} = 27

For

g^{3} (x) = f (a)

the solutions are

Solve

The solutions are

x = 1, x = - \frac{7}{2} + i \frac{3 3}{2}, x = - \frac{7}{2} - i \frac{3 3}{2}

x^{3} + 2 x^{2} + x + 1 = 0

- 2 x^{3} = 0

(x + 4) (x + 2) (x - 1) (x - 3) = 0

2 x^{3} + 7 x^{2} + 4 x - 4 = 0

x (x - 1)^{2} = - (x - 1) (3 x + 2)

What are the solutions to the equation (x+2)^3=27 ?
The solutions to the equation (x+2)^3=27 are x=1,x=-7/2+i(3sqrt(3))/2 ,x=-7/2-i(3sqrt(3))/2
Find the zeros of (x+2)^3=27
The zeros of (x+2)^3=27 are x=1,x=-7/2+i(3sqrt(3))/2 ,x=-7/2-i(3sqrt(3))/2