What are the solutions to the equation -x^3+12x^2-29x+18=0 ?

The solutions to the equation -x^3+12x^2-29x+18=0 are x=1,x=2,x=9

Find the zeros of -x^3+12x^2-29x+18=0

The zeros of -x^3+12x^2-29x+18=0 are x=1,x=2,x=9

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- x^{3} + 12 x^{2} - 29 x + 18 = 0

x = 1, x = 2, x = 9

Solution steps

- x^{3} + 12 x^{2} - 29 x + 18 = 0

Factor

- x^{3} + 12 x^{2} - 29 x + 18 : - (x - 1) (x - 2) (x - 9)

- (x - 1) (x - 2) (x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 2 = 0 or x - 9 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

Solve

x - 9 = 0 : x = 9

The solutions are

x = 1, x = 2, x = 9

715 = 5 x^{3}

4 x^{4} - x + 1 = 0

2 x (4 x^{4}) = (2 x^{5}) x^{4}

x^{3} - 16 x^{2} + 60 x = 0

z^{4} + 35 z^{2} - 36 = 0

What are the solutions to the equation -x^3+12x^2-29x+18=0 ?
The solutions to the equation -x^3+12x^2-29x+18=0 are x=1,x=2,x=9
Find the zeros of -x^3+12x^2-29x+18=0
The zeros of -x^3+12x^2-29x+18=0 are x=1,x=2,x=9