What are the solutions to the equation x^2(x-1)(x+2)=0 ?

The solutions to the equation x^2(x-1)(x+2)=0 are x=0,x=1,x=-2

Find the zeros of x^2(x-1)(x+2)=0

The zeros of x^2(x-1)(x+2)=0 are x=0,x=1,x=-2

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x^{2} (x - 1) (x + 2) = 0

x = 0, x = 1, x = - 2

Solution steps

x^{2} (x - 1) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x + 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

The solutions are

x = 0, x = 1, x = - 2

x^{3} - 2 x^{2} - 4 x + 3 = 0

x^{3} + x^{2} + 16 x + 16 = 0

x^{4} + 2 x^{3} - 13 x^{2} - 14 x + 24 = 0

x, x^{4} - 1 = 0

z^{4} = 1 - i

What are the solutions to the equation x^2(x-1)(x+2)=0 ?
The solutions to the equation x^2(x-1)(x+2)=0 are x=0,x=1,x=-2
Find the zeros of x^2(x-1)(x+2)=0
The zeros of x^2(x-1)(x+2)=0 are x=0,x=1,x=-2