What are the solutions to the equation x^4-36x^2=-35 ?

The solutions to the equation x^4-36x^2=-35 are x=sqrt(35),x=-sqrt(35),x=1,x=-1

Find the zeros of x^4-36x^2=-35

The zeros of x^4-36x^2=-35 are x=sqrt(35),x=-sqrt(35),x=1,x=-1

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x^{4} - 36 x^{2} = - 35

x = 35, x = - 35, x = 1, x = - 1

Decimal Notation

x = 5.91607 \dots, x = - 5.91607 \dots, x = 1, x = - 1

Solution steps

x^{4} - 36 x^{2} = - 35

Move

35

to the left side

x^{4} - 36 x^{2} + 35 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} - 36 u + 35 = 0

Solve

u^{2} - 36 u + 35 = 0 : u = 35, u = 1

u = 35, u = 1

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 35 : x = 35, x = - 35

Solve

x^{2} = 1 : x = 1, x = - 1

The solutions are

x = 35, x = - 35, x = 1, x = - 1

x^{4} - 6 x^{3} + 5 x^{2} = 0

3 x^{4} + 24 x = 0

x, e^{t} = x^{6}

4 x^{3} - 36 x^{2} - 96 x - 64 = 0

8 x^{3} - 8 = 0

What are the solutions to the equation x^4-36x^2=-35 ?
The solutions to the equation x^4-36x^2=-35 are x=sqrt(35),x=-sqrt(35),x=1,x=-1
Find the zeros of x^4-36x^2=-35
The zeros of x^4-36x^2=-35 are x=sqrt(35),x=-sqrt(35),x=1,x=-1