What are the solutions to the equation 3x^3+11x^2+6x=0 ?

The solutions to the equation 3x^3+11x^2+6x=0 are x=0,x=-2/3 ,x=-3

Find the zeros of 3x^3+11x^2+6x=0

The zeros of 3x^3+11x^2+6x=0 are x=0,x=-2/3 ,x=-3

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3 x^{3} + 11 x^{2} + 6 x = 0

x = 0, x = - \frac{2}{3}, x = - 3

Decimal Notation

x = 0, x = - 0.66666 \dots, x = - 3

Solution steps

3 x^{3} + 11 x^{2} + 6 x = 0

Factor

3 x^{3} + 11 x^{2} + 6 x : x (3 x + 2) (x + 3)

x (3 x + 2) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x + 2 = 0 or x + 3 = 0

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

x + 3 = 0 : x = - 3

The solutions are

x = 0, x = - \frac{2}{3}, x = - 3

x^{3} + 4 x^{2} + 4 x + 16 = 0

x^{3} - 25 x^{2} = 0

4 s^{3} + 36 s^{2} + 128 s + 128 = 0

20 x + 8 x^{2} - x^{3} = 0

- 10 x - (9 x + 6) = 3 + x^{3} + x

What are the solutions to the equation 3x^3+11x^2+6x=0 ?
The solutions to the equation 3x^3+11x^2+6x=0 are x=0,x=-2/3 ,x=-3
Find the zeros of 3x^3+11x^2+6x=0
The zeros of 3x^3+11x^2+6x=0 are x=0,x=-2/3 ,x=-3