What are the solutions to the equation -2x^3-x^2+8x-5=0 ?

The solutions to the equation -2x^3-x^2+8x-5=0 are x=1,x=-5/2

Find the zeros of -2x^3-x^2+8x-5=0

The zeros of -2x^3-x^2+8x-5=0 are x=1,x=-5/2

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- 2 x^{3} - x^{2} + 8 x - 5 = 0

x = 1, x = - \frac{5}{2}

Solution steps

- 2 x^{3} - x^{2} + 8 x - 5 = 0

Factor

- 2 x^{3} - x^{2} + 8 x - 5 : - (x - 1)^{2} (2 x + 5)

- (x - 1)^{2} (2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x + 5 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x + 5 = 0 : x = - \frac{5}{2}

The solutions are

x = 1, x = - \frac{5}{2}

(x^{3}) (x + 3) = 5

0 = 12 x^{3} - 12 x^{2}

y^{3} + 5 y^{2} - 49 y - 245 = 0

x^{3} + 6 x^{2} - 9 x + 4 = 0

y, y^{3} = x^{3} - 9 x

What are the solutions to the equation -2x^3-x^2+8x-5=0 ?
The solutions to the equation -2x^3-x^2+8x-5=0 are x=1,x=-5/2
Find the zeros of -2x^3-x^2+8x-5=0
The zeros of -2x^3-x^2+8x-5=0 are x=1,x=-5/2