What are the solutions to the equation 0=3x^3+8x^2-15x+4 ?

The solutions to the equation 0=3x^3+8x^2-15x+4 are x=1,x= 1/3 ,x=-4

Find the zeros of 0=3x^3+8x^2-15x+4

The zeros of 0=3x^3+8x^2-15x+4 are x=1,x= 1/3 ,x=-4

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0 = 3 x^{3} + 8 x^{2} - 15 x + 4

x = 1, x = \frac{1}{3}, x = - 4

Decimal Notation

x = 1, x = 0.33333 \dots, x = - 4

Solution steps

0 = 3 x^{3} + 8 x^{2} - 15 x + 4

Switch sides

3 x^{3} + 8 x^{2} - 15 x + 4 = 0

Factor

3 x^{3} + 8 x^{2} - 15 x + 4 : (x - 1) (3 x - 1) (x + 4)

(x - 1) (3 x - 1) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 3 x - 1 = 0 or x + 4 = 0

Solve

x - 1 = 0 : x = 1

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

x + 4 = 0 : x = - 4

The solutions are

x = 1, x = \frac{1}{3}, x = - 4

2 z^{4} + 32 = 0

k^{4} - 3 k^{3} - 3 k^{2} + 5 k = 0

4 x (x^{2} - 2) = 0

x^{3} + x^{2} - 3 x - 6 = 0

(x + 1)^{4} = 0

What are the solutions to the equation 0=3x^3+8x^2-15x+4 ?
The solutions to the equation 0=3x^3+8x^2-15x+4 are x=1,x= 1/3 ,x=-4
Find the zeros of 0=3x^3+8x^2-15x+4
The zeros of 0=3x^3+8x^2-15x+4 are x=1,x= 1/3 ,x=-4