What are the solutions to the equation (2x-1)(x^2-14)=0 ?

The solutions to the equation (2x-1)(x^2-14)=0 are x= 1/2 ,x=-sqrt(14),x=sqrt(14)

Find the zeros of (2x-1)(x^2-14)=0

The zeros of (2x-1)(x^2-14)=0 are x= 1/2 ,x=-sqrt(14),x=sqrt(14)

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(2 x - 1) (x^{2} - 14) = 0

x = \frac{1}{2}, x = - 14, x = 14

Solution steps

(2 x - 1) (x^{2} - 14) = 0

Factor

(2 x - 1) (x^{2} - 14) : (2 x - 1) (x + 14) (x - 14)

(2 x - 1) (x + 14) (x - 14) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or x + 14 = 0 or x - 14 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 14 = 0 : x = - 14

Solve

x - 14 = 0 : x = 14

The solutions are

x = \frac{1}{2}, x = - 14, x = 14

4 x^{4} + 7 x^{2} - 36 = 0

x^{3} + 3 = 57

x^{4} - 6 x^{3} + 11 x^{2} - 8 x + 2 = 0

x^{4} - 3 x^{2} - 70 = 0

- 10 n^{3} - 15 n^{4} = 5 n^{3}

What are the solutions to the equation (2x-1)(x^2-14)=0 ?
The solutions to the equation (2x-1)(x^2-14)=0 are x= 1/2 ,x=-sqrt(14),x=sqrt(14)
Find the zeros of (2x-1)(x^2-14)=0
The zeros of (2x-1)(x^2-14)=0 are x= 1/2 ,x=-sqrt(14),x=sqrt(14)