What are the solutions to the equation (4w+3)(w+4)(w-2)(w+6)=0 ?

The solutions to the equation (4w+3)(w+4)(w-2)(w+6)=0 are w=-3/4 ,w=-4,w=2,w=-6

Find the zeros of (4w+3)(w+4)(w-2)(w+6)=0

The zeros of (4w+3)(w+4)(w-2)(w+6)=0 are w=-3/4 ,w=-4,w=2,w=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(4 w + 3) (w + 4) (w - 2) (w + 6) = 0

w = - \frac{3}{4}, w = - 4, w = 2, w = - 6

Solution steps

(4 w + 3) (w + 4) (w - 2) (w + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 w + 3 = 0 or w + 4 = 0 or w - 2 = 0 or w + 6 = 0

Solve

4 w + 3 = 0 : w = - \frac{3}{4}

Solve

w + 4 = 0 : w = - 4

Solve

w - 2 = 0 : w = 2

Solve

w + 6 = 0 : w = - 6

The solutions are

w = - \frac{3}{4}, w = - 4, w = 2, w = - 6

- 2 x (x + 7) (x^{2} - 11) = 0

x^{3} - x^{2} + 5 x - 5 = 0

x^{3} - 4 x^{2} - x - 4 = 0

20 x^{2} - 32 x - 2 x^{3} = 0

(x + 4)^{3} - 9 x = 36

What are the solutions to the equation (4w+3)(w+4)(w-2)(w+6)=0 ?
The solutions to the equation (4w+3)(w+4)(w-2)(w+6)=0 are w=-3/4 ,w=-4,w=2,w=-6
Find the zeros of (4w+3)(w+4)(w-2)(w+6)=0
The zeros of (4w+3)(w+4)(w-2)(w+6)=0 are w=-3/4 ,w=-4,w=2,w=-6