What are the solutions to the equation 7=56x^3 ?

The solutions to the equation 7=56x^3 are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i

Find the zeros of 7=56x^3

The zeros of 7=56x^3 are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i

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7 = 56 x^{3}

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

Solution steps

7 = 56 x^{3}

Switch sides

56 x^{3} = 7

Divide both sides by

56

x^{3} = \frac{1}{8}

For

x^{3} = f (a)

the solutions are

Simplify

x = \frac{1}{2}, x = - \frac{1}{4} + \frac{3}{4} i, x = - \frac{1}{4} - \frac{3}{4} i

2 x^{3} - x^{2} + 32 x - 16 = 0

x^{4} - 10 x + 5 = 0

2 x^{3} - 2 x^{2} - 5 x = 3

x^{4} + 12 x^{3} - 64 x^{2} = 0

x^{4} + 3 x^{2} - 54 = 0

What are the solutions to the equation 7=56x^3 ?
The solutions to the equation 7=56x^3 are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i
Find the zeros of 7=56x^3
The zeros of 7=56x^3 are x= 1/2 ,x=-1/4+(sqrt(3))/4 i,x=-1/4-(sqrt(3))/4 i