What are the solutions to the equation x^4+12x^3-64x^2=0 ?

The solutions to the equation x^4+12x^3-64x^2=0 are x=0,x=4,x=-16

Find the zeros of x^4+12x^3-64x^2=0

The zeros of x^4+12x^3-64x^2=0 are x=0,x=4,x=-16

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x^{4} + 12 x^{3} - 64 x^{2} = 0

x = 0, x = 4, x = - 16

Solution steps

x^{4} + 12 x^{3} - 64 x^{2} = 0

Factor

x^{4} + 12 x^{3} - 64 x^{2} : x^{2} (x - 4) (x + 16)

x^{2} (x - 4) (x + 16) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 4 = 0 or x + 16 = 0

Solve

x - 4 = 0 : x = 4

Solve

x + 16 = 0 : x = - 16

The solutions are

x = 0, x = 4, x = - 16

x^{4} + 3 x^{2} - 54 = 0

x^{5} + x^{2} + 1 = 0

(x - 3) (x + 4) (x + 6) = 0

0 = x^{3} + 2 x^{2} - 6 x + 8

16 x^{3} - 8 x^{2} = 0

What are the solutions to the equation x^4+12x^3-64x^2=0 ?
The solutions to the equation x^4+12x^3-64x^2=0 are x=0,x=4,x=-16
Find the zeros of x^4+12x^3-64x^2=0
The zeros of x^4+12x^3-64x^2=0 are x=0,x=4,x=-16