What are the solutions to the equation (x-3)(x+4)(x+6)=0 ?

The solutions to the equation (x-3)(x+4)(x+6)=0 are x=3,x=-4,x=-6

Find the zeros of (x-3)(x+4)(x+6)=0

The zeros of (x-3)(x+4)(x+6)=0 are x=3,x=-4,x=-6

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(x - 3) (x + 4) (x + 6) = 0

x = 3, x = - 4, x = - 6

Solution steps

(x - 3) (x + 4) (x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 4 = 0 or x + 6 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 4 = 0 : x = - 4

Solve

x + 6 = 0 : x = - 6

The solutions are

x = 3, x = - 4, x = - 6

0 = x^{3} + 2 x^{2} - 6 x + 8

16 x^{3} - 8 x^{2} = 0

x^{3} - 4 x^{2} + 2 x + 3 = 0

2 x^{3} + x^{2} + x + 1 = 0

h, 5 h (h^{2} + 12) = 68

What are the solutions to the equation (x-3)(x+4)(x+6)=0 ?
The solutions to the equation (x-3)(x+4)(x+6)=0 are x=3,x=-4,x=-6
Find the zeros of (x-3)(x+4)(x+6)=0
The zeros of (x-3)(x+4)(x+6)=0 are x=3,x=-4,x=-6