What are the solutions to the equation 0=x^3+2x^2-6x+8 ?

The solutions to the equation 0=x^3+2x^2-6x+8 are x=-4,x=1+i,x=1-i

Find the zeros of 0=x^3+2x^2-6x+8

The zeros of 0=x^3+2x^2-6x+8 are x=-4,x=1+i,x=1-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{3} + 2 x^{2} - 6 x + 8

x = - 4, x = 1 + i, x = 1 - i

Solution steps

0 = x^{3} + 2 x^{2} - 6 x + 8

Switch sides

x^{3} + 2 x^{2} - 6 x + 8 = 0

Factor

x^{3} + 2 x^{2} - 6 x + 8 : (x + 4) (x^{2} - 2 x + 2)

(x + 4) (x^{2} - 2 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x^{2} - 2 x + 2 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x^{2} - 2 x + 2 = 0 : x = 1 + i, x = 1 - i

The solutions are

x = - 4, x = 1 + i, x = 1 - i

16 x^{3} - 8 x^{2} = 0

x^{3} - 4 x^{2} + 2 x + 3 = 0

2 x^{3} + x^{2} + x + 1 = 0

h, 5 h (h^{2} + 12) = 68

- 3 x^{5} + 5 x^{3} = 0

What are the solutions to the equation 0=x^3+2x^2-6x+8 ?
The solutions to the equation 0=x^3+2x^2-6x+8 are x=-4,x=1+i,x=1-i
Find the zeros of 0=x^3+2x^2-6x+8
The zeros of 0=x^3+2x^2-6x+8 are x=-4,x=1+i,x=1-i