What are the solutions to the equation x^3-4x^2+19x+5=0 ?

The solutions to the equation x^3-4x^2+19x+5=0 are x\approx-0.24926…

Find the zeros of x^3-4x^2+19x+5=0

The zeros of x^3-4x^2+19x+5=0 are x\approx-0.24926…

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x^{3} - 4 x^{2} + 19 x + 5 = 0

x \approx - 0.24926 \dots

Solution steps

x^{3} - 4 x^{2} + 19 x + 5 = 0

Find one solution for

x^{3} - 4 x^{2} + 19 x + 5 = 0

using Newton-Raphson:

x \approx - 0.24926 \dots

Apply long division:

\frac{x ^{3} - 4 x ^{2} + 19 x + 5}{x + 0.24926 \dots} = x^{2} - 4.24926 \dots x + 20.05918 \dots

x^{2} - 4.24926 \dots x + 20.05918 \dots \approx 0

Find one solution for

x^{2} - 4.24926 \dots x + 20.05918 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx - 0.24926 \dots

(x^{4} - 3 x^{3} - 2 x^{2} - 3 x + 1) = 0

h^{3} = 64

\frac{( 35 x - 50 )}{5} = 2 x^{15}

- 10 x^{3} + 6 x^{2} + 90 x - 54 = 0

- y^{3} + 5 y^{2} - 7 y + 3 = 0

What are the solutions to the equation x^3-4x^2+19x+5=0 ?
The solutions to the equation x^3-4x^2+19x+5=0 are x\approx-0.24926…
Find the zeros of x^3-4x^2+19x+5=0
The zeros of x^3-4x^2+19x+5=0 are x\approx-0.24926…