What are the solutions to the equation 31=4(x^2+2)^3-1 ?

The solutions to the equation 31=4(x^2+2)^3-1 are

Find the zeros of 31=4(x^2+2)^3-1

The zeros of 31=4(x^2+2)^3-1 are

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31 = 4 (x^{2} + 2)^{3} - 1

x = 0, x = \frac{- 3 + 2 3}{2} + \frac{3}{2 - 3 + 2 3} i, x = - \frac{- 3 + 2 3}{2} - \frac{3}{2 - 3 + 2 3} i, x = \frac{- 3 + 2 3}{2} - \frac{3}{2 - 3 + 2 3} i, x = - \frac{- 3 + 2 3}{2} + \frac{3}{2 - 3 + 2 3} i

Solution steps

31 = 4 (x^{2} + 2)^{3} - 1

Switch sides

4 (x^{2} + 2)^{3} - 1 = 31

Move

1

to the right side

4 (x^{2} + 2)^{3} = 32

Divide both sides by

4

(x^{2} + 2)^{3} = 8

For

g^{3} (x) = f (a)

the solutions are

Solve

The solutions are

x = 0, x = \frac{- 3 + 2 3}{2} + \frac{3}{2 - 3 + 2 3} i, x = - \frac{- 3 + 2 3}{2} - \frac{3}{2 - 3 + 2 3} i, x = \frac{- 3 + 2 3}{2} - \frac{3}{2 - 3 + 2 3} i, x = - \frac{- 3 + 2 3}{2} + \frac{3}{2 - 3 + 2 3} i

3 x^{4} - 4 x^{3} - 12 x^{2} + 3 = 0

x^{6} + 3 x^{3} - 6 = 0

x^{4} + 3 x^{2} + 1 = 0

x^{4} - 4 x^{3} + 2 x^{2} + 4 x - 3 = 0

80 = - 0.001 x^{3} + 0.18 x^{2} + 60

What are the solutions to the equation 31=4(x^2+2)^3-1 ?
The solutions to the equation 31=4(x^2+2)^3-1 are
Find the zeros of 31=4(x^2+2)^3-1
The zeros of 31=4(x^2+2)^3-1 are