What are the solutions to the equation (w-3)^2(w+1)^2=0 ?

The solutions to the equation (w-3)^2(w+1)^2=0 are w=3,w=-1

Find the zeros of (w-3)^2(w+1)^2=0

The zeros of (w-3)^2(w+1)^2=0 are w=3,w=-1

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(w - 3)^{2} (w + 1)^{2} = 0

w = 3, w = - 1

Solution steps

(w - 3)^{2} (w + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

w - 3 = 0 or w + 1 = 0

Solve

w - 3 = 0 : w = 3

Solve

w + 1 = 0 : w = - 1

The solutions are

w = 3, w = - 1

5 = \frac{4}{3} π x^{3}

x^{8} + x^{5} + x^{2} - x + 1 = 0

8 x (x^{2} - 1)^{3} = 0

0 = y^{2} - y^{3}

x^{3} + 2 x - 1 = 2

What are the solutions to the equation (w-3)^2(w+1)^2=0 ?
The solutions to the equation (w-3)^2(w+1)^2=0 are w=3,w=-1
Find the zeros of (w-3)^2(w+1)^2=0
The zeros of (w-3)^2(w+1)^2=0 are w=3,w=-1