What are the solutions to the equation -a^3-2a^2+4a+8=0 ?

The solutions to the equation -a^3-2a^2+4a+8=0 are a=-2,a=2

Find the zeros of -a^3-2a^2+4a+8=0

The zeros of -a^3-2a^2+4a+8=0 are a=-2,a=2

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- a^{3} - 2 a^{2} + 4 a + 8 = 0

a = - 2, a = 2

Solution steps

- a^{3} - 2 a^{2} + 4 a + 8 = 0

Factor

- a^{3} - 2 a^{2} + 4 a + 8 : - (a + 2)^{2} (a - 2)

- (a + 2)^{2} (a - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a + 2 = 0 or a - 2 = 0

Solve

a + 2 = 0 : a = - 2

Solve

a - 2 = 0 : a = 2

The solutions are

a = - 2, a = 2

x^{3} - 7 x - 3 = 0

a, y = 9 a^{4} - a^{2} b^{2}

r, f = - 1 r^{8}

1 - 4 x^{2} - 4 x^{4} = 0

8 = x^{5}

What are the solutions to the equation -a^3-2a^2+4a+8=0 ?
The solutions to the equation -a^3-2a^2+4a+8=0 are a=-2,a=2
Find the zeros of -a^3-2a^2+4a+8=0
The zeros of -a^3-2a^2+4a+8=0 are a=-2,a=2